But the definition that CLRS uses for "running time" is particular, and not the same as you might encounter in other resources.ĬLRS assumes here that a primitive operation (i.e. So while we would normally consider these two terms to have the same meaning, in CLRS they have deviated from that, and gave a different meaning to "running time".ĭoes running time describe the number of steps executed or not? Most would agree that "runnning" and "executing" are the same concept, and that "time" is expressed in a unit of time (like milliseconds). This is not what you would intuitively use as a definition. The definition of "running time" in 'Introduction to Algorithms' by C,L,R,S is actually not a time, but a number of steps. What is the real meaning or definition of running time and execution time? Are they the same of different?
In practice, you should not expect such optimizations, as the Stream implementation code is too complex for the optimizer. This behavioral compatibility implies that even if the processing gets optimized away, a peek(System.out::println) would keep printing all elements as if they were processed. However, this requires inlining of all involved methods to be sure that this conditions always applies and there are no side effect which must be retained.
But the responsibility lies at the JVM’s optimizer which might do the same for loops. This does not mean that such optimizations based on logic or algebra are impossible. This is a short-circuiting terminal operation. Go to the Stream API documentation and check whether the particular terminal operation’s documentation contains the sentence This is always the case, so when you don’t chain a terminal operation, no intermediate operation will ever process any element.įinding out whether a terminal operation is short-circuiting, is rather easy. The term “lazy” only applies to intermediate operations and means that they only perform work when being requested by the terminal operation. Having a short-circuiting operation in the pipeline is a necessary, but not sufficient, condition for the processing of an infinite stream to terminate normally in finite time. A terminal operation is short-circuiting if, when presented with infinite input, it may terminate in finite time. An intermediate operation is short-circuiting if, when presented with infinite input, it may produce a finite stream as a result.
The actual term you’re asking for is short-circuitingįurther, some operations are deemed short-circuiting operations. Sb = 5 / 4 * (la.thickness - 4 * z3 / thickness ** 2) # Calculate H matrix (derived from Barbero:2018, p. # Calculate unit thermal stress resultants.